1912 Vermont gubernatorial election
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The 1912 Vermont gubernatorial election took place on September 3, 1912. Incumbent Republican John A. Mead, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Allen M. Fletcher defeated Democratic candidate Harland B. Howe and Progressive candidate Fraser Metzger to succeed him. Since no candidate won a majority of the popular vote, the election was decided and Fletcher was elected by the Vermont General Assembly in accordance with the state constitution.[2]
This was the last time until 1986 that none of the gubernatorial candidates received a majority of the vote.[3]
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Allen M. Fletcher | 26,237 | 40.5 | ||
| Democratic | Harland B. Howe | 20,001 | 30.8 | ||
| Progressive | Fraser Metzger | 15,629 | 24.1 | ||
| Prohibition | Clement F. Smith | 1,735 | 2.7 | ||
| Socialist | Fred W. Suitor | 1,210 | 1.9 | ||
| N/A | Other | 27 | 0.0 | ||
| Total votes | '64,839' | '100' | |||
References
- ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
- ^ a b "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.
- ^ Doyle 1992, p. 222.
Works cited
- Doyle, William (1992). The Vermont Political Tradition: And Those Who Helped Make It. ISBN 0961548614.
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