Election in Alabama
1880 United States presidential election in Alabama
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Turnout | 12.03% of the total population 5.19 pp[1] |
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| | | Nominee | Winfield S. Hancock | James A. Garfield | | Party | Democratic | Republican | Home state | Pennsylvania | Ohio | Running mate | William H. English | Chester A. Arthur | Electoral vote | 10 | 0 | Popular vote | 91,130 | 56,350 | Percentage | 59.99% | 37.10% | |
County results Hancock 40–50% 50–60% 60–70% 70–80% 80–90% 90–100% | Garfield 40–50% 50–60% 60–70% 80–90% | |
President before election Rutherford B. Hayes Republican | Elected President James A. Garfield Republican | |
Elections in Alabama |
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The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the nationwide presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Alabama was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee, Chester A. Arthur, with 37.10% of the vote.[2]
Results
See also
References
- ^ "1884 Presidential Election Results Alabama Total Population Turnout".
- ^ a b c "1880 Presidential Election Results Alabama".
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